**Problem : **
What dimensions do you need to know to determine the value of `arr[3][5][7]`
using only pointer arithmetic and the dereference operator (*)?

You do not need to know the first dimension, but you do need to know
the second and the third dimension. In general you need to know all but
the first dimension.

**Problem : **
Assuming that the second dimension were `SECOND` and the third
dimension were `THIRD`, calculate the value of `arr[3][5][7]` from the
pointer `arr` using pointer arithmetic and the dereference operator.

The equivalent is:

*(arr + 3 * SECOND * THIRD + 5 * THIRD + 7)

In general you multiply each index by the size of the greater
dimensions. So the first index, 3, is multiplied by the second and
third dimensions and the second index, 5, is multiplied by the third
dimension.

**Problem : **
As an exercise, write some code that will print out all of the integers
in the integer array without ever using the square brackets to index
into it. There are `n` integers in the array `arr`.

int i;
for(i = 0; i < n; i++)
{
printf("%i\n", *(arr + i);
}